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MHT CET202522 Apr 2025Evening ShiftPhysicsThermal Properties of MatterActual

The two ends of a rod of length ' x ' and uniform cross-sectional area ' A ' are kept at temperatures ' T₁ ' and ' T₂ ' respectively ( T₁>T₂ ). If the rate of heat transfer is ' Q / t ', through the rod in steady state, then the coefficient of thermal conductivity ' K ' is

Options

  1. AAQ tx ( T ₁- T ₂ )
  2. Bx Q t A (T₁-T₂ )
  3. CxAQ t ( T ₁- T ₂ )
  4. DQ txA ( T ₁- T ₂ )

Correct answer

B. x Q t A (T₁-T₂ )

Step-by-step solution

The rate of heat conduction through a rod in steady state follows Fourier's law: Q t = KA T₁ - T₂ x . Coefficient of thermal conductivity K is obtained by rearranging: K = xQ tA(T₁ - T₂) . This matches the expression in option B.

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