Black bodies A and B radiate maximum energy with wavelength difference 4 ~m . The absolute temperature of body A is 3 times that of B. The wavelength at which body B radiates maximum energy is

Step-by-step solution

According to Wien’s displacement law, _m T = b for any black body, where _m is the peak wavelength, T is absolute temperature, and b is Wien’s constant. Given T_A = 3T_B , from _ mA T_A = _ mB T_B , substitution yields 3 _ mA = _ mB . With _ mB - _ mA = 4 , m , substitute to obtain 3 _ mA - _ mA = 4 , m , so 2 _ mA = 4 , m and _ mA = 2 , m . Then _ mB = 3 2 , m = 6 , m . Thus, body B radiates maximum energy at 6 , m .