If 120 J of thermal energy is incident on area 3 ~m ^2 , the amount of heat transmitted is 12 J, coefficient of absorption is 0.6 , then the amount of heat reflected is

Step-by-step solution

The total incident thermal energy Q_ incident = 120 J follows the conservation principle: Q_ incident = Q_ absorbed + Q_ reflected + Q_ transmitted Given the absorption coefficient a = 0.6 and transmitted energy Q_ transmitted = 12 J , the absorbed energy is: Q_ absorbed = a Q_ incident = 0.6 120 = 72 J Substituting into the conservation equation: 120 = 72 + Q_ reflected + 12Q_ reflected = 120 - (72 + 12) = 36 J Final answer: 36 J