A rectangular block of surface area A emits energy E per second at 27^ C . If length and breadth is reduced to half of initial value and temperature is raised to 327^ C then energy emitted per second becomes

Step-by-step solution

The Stefan-Boltzmann Law E = A T^4 relates the energy radiated per second to surface area and temperature. Given the initial conditions A₁ = A and T₁ = 300 , K , the energy emitted is E₁ = E . When the length and breadth are halved, the surface area becomes A₂ = A/4 . The temperature is T₂ = 600 , K . The ratio of energies is E₂ E₁ = A₂ A₁ ( T₂ T₁ )^4 = 1 4 2^4 = 4 . The energy emitted per second becomes 4E .