Rate of radiation by a black body is 'R' at temperature 'T'. Another body has same area but emissivity is 0.2 and temperature 3 T . Its rate of radiation is

Step-by-step solution

Rate of radiation for blackbody, R = ( dQ dt )₁= eA ~T ^4= A ~T ^4 ( e =1) For another body, aligned ( dQ dt )₂ & = e ^ A ^ ( T ^ )^4 & =0.2 ~A (3 ~T )^4 & =16.2 ~A ~T ^4 & =16.2 ( dQ dt )₁=16. 2 R aligned