The temperature of a liquid falls from 365 K to 359 K in 3 minutes. The time during which temperature of this liquid falls from 342 K to 338 K is [Let the room temperature be 296 K ]

Step-by-step solution

From Newton's law of cooling, T ₁- T ₂ t = K ( ~T ₁+ T ₂ 2 - T ₀ ) where T₀ is the room temperature. For decrease from 365 K to 359 K , aligned & 365-359 3 = K [ 365+359 2 -296 ] & K = 1 33 aligned For decrease from 342 K to 338 K , 342-338 t = 1 33 [ 342+338 2 -296 ] aligned & 4 t = 4 3 & t=3 ~min aligned