Two bodies ' X ' and ' Y ' at temperatures ' T ₁ ' K and ' T ₂ ' K respectively have the same dimensions. If their emissive powers are same, the relation between their temperatures is

Step-by-step solution

Given: - Two bodies X and Y at temperatures T₁ and T₂ . - Same dimensions. - Same emissive power. Stefan-Boltzmann Law: E= e A T^4 Here: - E: Emissive power, - : Stefan-Boltzmann constant, - e: Emissivity, - A: Surface area, - T: Absolute temperature. For the same emissive power: T₁^4=T₂^4 If T₁ / T₂=1 / 3 , then: T₁^4 / T₂^4=1 / 81 T₁ / T₂= 1 3 . Answer: T₁ / T₂= 1 3 , Option 1.