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AP EAMCET202022 Sep 2020Evening ShiftMathematicsCircleActual

If the circle x^2+y^2+6 x-2 y+k=0 bisects the circumference of the circle x^2+y^2+2 x-6 y-15=0 , then ' k ' is equal to

Options

  1. A21
  2. B–21
  3. C23
  4. D–23

Correct answer

D. –23

Step-by-step solution

Given, equation of circles are aligned & S: x^2+y^2+6 x-2 y+k=0 & S^ : x^2+y^2+2 x-6 y-15=0 aligned Centre =(-1,3) Equation of common chaod is S-S^ =0 4 x+4 y+(k+15)=0 Centre of S^ lies on the above line (-1,3) lies on Eq. (i) 4(-1)+4(3)+k+15=0 k=-23 Hence, option (4) is correct.

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