Two bodies A and B radiate maximum energy with wavelength difference 4 m . The absolute temperature of body A is 3 times that of B . The wavelength at which body B radiates maximum energy is:

Step-by-step solution

Concept: According to the Wiens displacement law: _m T= Constant, Given ( _ m B - _ m A )=4 m ---(1)T_A=3 T_B ---(2) Now, using Wens law T_A= _ m B T_B ---(3) Eq ^ n (2) divided by Eq ^ n (3) aligned & 1 _ m A = 3 _ m B & _ m B _ m A =3 & ( _ m B - _ m A ) _ m A =2 & _ m A = 1 2 ( _ m B - _ m A ) aligned Now, using eq ^ n 1 aligned & _ m A = 1 2 (4 m )=2 m & _ m B =4 + _ m A =6 m aligned