MHT CET202124 Sep 2021Morning ShiftPhysicsThermal Properties of MatterActual
A cylindrical rod has temperature ' T ₁ ' and ' T ₂ ' at its ends. The rate of flow of heat is ' Q ₁ ' cal s ⁻¹ . If length and radius of the rod are doubled keeping temperature constant, then the rate of flow of heat ' Q₂ ' will be
Options
- AQ ₂= Q ₁ 2
- BQ ₂= Q ₁ 4
- CQ ₂=4 Q ₁
- DQ ₂=2 Q ₁
Correct answer
D. Q ₂=2 Q ₁
Step-by-step solution
aligned & Q ₁= kA ( T ₁- T ₂ ) L ₁ = k r ₁^2 ( ~T ₁- T ₂ ) L ₁ & Q ₂= k r ₂^2 ( ~T ₁- T ₂ ) L ₂ & Q ₂ Q ₁ = r ₂^2 r ₁^2 L ₁ ~L ₂ =(2)^2 1 2 =2 & Q ₂=2 Q ₁ aligned