MHT CET202122 Sep 2021Morning ShiftPhysicsThermal Properties of MatterActual
A cylindrical rod is having temperatures ₁ and ₂ at its ends. The rate of heat flow is ' Q ' J s ⁻¹ . All the linear dimensions of the rod are doubled by keeping the temperatures constant. What is the new rate of flow of heat?
Options
- AQ 2
- BQ 4
- C2 Q
- D3 Q 2
Correct answer
C. 2 Q
Step-by-step solution
Q = kA If the radius of the cylindrical rod is doubled, then its area of cross-section will become four times. aligned & A ₂=4 ~A ₁ & Also, ₂=2 ₁ & Q ^ Q = A ₂ ~A ₁ d ₁ ~d ₂ =4 1 2 =2 & Q ^ =2 Q aligned