The maximum wavelength of radiation emitted by a star is 289.8 nm. Then intensity of radiation for the star is (Given : Stefan’s constant = 5.67 × 10 - 8 W m - 2 K - 4 , Wien’s constant, b = 2898 μ m K )

Step-by-step solution

Given, maximum wavelength, λ m = 289.8 n m = 28.98 × 10 - 9 m = 2898 × 10 - 10 m Stefan’s constant, σ = 5.67 × 10 - 8 W m - 2 K - 4 Wien’s constant, b = 2898 μ m k = 2898 × 10 - 6 m K According to Wien’s displacement law, the maximum wavelength is given by λ m = b T ⇒ T = b λ m …. (i) Substituting given values in Eq. (i), we get T = 2898 × 10 - 6 2898 × 10 - 10 = 10 4 K …. (ii) According to Stefan’s law the energy radiated from a source is given by E = σ A e T 4 …. (iii) Where, A = area of source e = emissivity (va