If 150 ~J of energy is incident on area 2 ~m ² . If Q_ r =15 ~J , coefficient of absorption is 0.6 , then amount of energy transmitted is

Step-by-step solution

When thermal radiations (Q) fall on a body, they are partly reflected, partly absorbed and partly transmitted. Q=Q_ a +Q_ r +Q_ t and Q_ a Q + Q_ r Q + Q_ t Q =a+r+t=1 15 150 +0.6+x=1 or 0.1+0.6+x=1 or x=0.3 Transmitting power, t= Q_ t Q or 0.3= Q_ t 150 Q_ t =45 ~J