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AP EAMCET202022 Sep 2020Morning ShiftMathematicsCircleActual

For the circle x^2+y^2-9=0 , find the equation of the chord having (1,2) as its mid-point.

Options

  1. Ax+2 y+5=0
  2. Bx-3 y-5=0
  3. Cx-3 y+5=0
  4. Dx+2 y-5=0

Correct answer

D. x+2 y-5=0

Step-by-step solution

Equation of chord having mid-point (1,2) w.r.t. circle x^2+y^2-9=0 is (1) x+ (2) y-9=1^2+2^2-9 x+2 y=5

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