An ideal gas having pressure P, volume V and temperature T undergoes a thermodynamic process in which dW = 0 and dQ < 0 . Then, for the gas

Step-by-step solution

From the first law of thermodynamics, we have dQ = dU + dW . Given that dW = 0 , the process is isochoric, meaning the volume V remains constant. Substituting dW = 0 into the first law gives dU = dQ . Since it is given that dQ For an ideal gas, the change in internal energy is given by dU = nC_v dT . Since dU Using the ideal gas equation PV = nRT , since V is constant and T decreases, the pressure P must also decrease. Answer: T will decrease.