An ideal monoatomic gas is taken around the cycle ABCDA as shown in the P.V diagram. The work done during the cycle is

Step-by-step solution

The work done in a cyclic process represented on a P-V diagram is given by the area enclosed by the cycle. The given cycle ABCDA is a rectangle in the counter-clockwise direction. Area of the rectangle = (change in volume) (change in pressure) Area = (V_B - V_A) (P_C - P_B) From the graph, V_B = 3V₀ , V_A = V₀ , P_C = 2P₀ , and P_B = P₀ . Area = (3V₀ - V₀) (2P₀ - P₀) Area = (2V₀) (P₀) = 2P₀V₀ Since the cycle ABCDA is traversed in the counter-clockwise direction, the net work done is negative. Therefore, the work do