Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET202022 Sep 2020Morning ShiftMathematicsCircleActual

If the lines joining the origin to the points of intersection of y=m x+1 and x^2+y^2=1 are perpendicular, then .........

Options

  1. Am=-1 only
  2. Bm=1 only
  3. Cm= 1
  4. Dm=0

Correct answer

C. m= 1

Step-by-step solution

Equation of line joining origin to the points of intersection of y=m x+1 and x^2+y^2=1 is array rlrl x^2+y^2 & =(y-m x)^2 & & x^2+y^2 & =y^2-2 m x y+m^2 x^2 & & (1-m^2 ) x^2+2 m x y & =0 array The line are perpendicular if coefficient of x^2+ coefficient of y^2=0 1-m^2+0=0 m= 1

Practice Circle on Quantrex Academy →

More from Circle

A circle touches both the coordinate axes and the straight line L 4 x +3 y -6=0 in the first quadrant. If this circle lies below the line L =0 , then the equation of that circle is 2025If the smallest circle through the points of intersection of x^2+y^2=a^2 and x +y =p, 0 < p < a is x^2+y^2-a^2+ (x +y -p)=0 then = 2025If the lines 3 x-4 y+4=0 and 6 x-8 y-7=0 are the tangents to the same circle, then the area of that circle (in sq.units) is 2025Circles are drawn through the point (2,0) to cut intercepts of length 5 units on the X -axis. If their centre lie in the first quadrant, then their equation is 2025The circles x^2+y^2-2 x-4 y-4=0 and x^2+y^2+2 x+4 y-11=0 2025If the line 4 x-3 y+7=0 touches the circle x^2+y^2-6 x+4 y-12=0 at ( , ) , then +2 = 2025The slope of the common tangent drawn to the circles x^2+y^2-4 x+12 y-216=0 and x^2+y^2+6 x-12 y+36=0 is 2025If r₁ and r₂ are radii of two circles touching all the four circles (x r)^2+(y r)^2=r^2 , then r₁+r₂ r = 2025 Full Circle list All AP EAMCET PYQs