Carnot engine operating between temperatures T₁ and T₂ has efficiency 0.2 . When T₂ is lowered by 45 K, its efficiency becomes 0.5 . Temperatures T₁ and T₂ are respectively

Step-by-step solution

Efficiency of a Carnot engine is given by = 1 - T₂ T₁ Given = 0.2 1 - T₂ T₁ = 0.2 T₂ T₁ = 0.8 T₂ = 0.8 T₁ When T₂ is lowered by 45 K, efficiency becomes 0.5 1 - T₂ - 45 T₁ = 0.5 T₂ - 45 T₁ = 0.5 T₂ - 45 = 0.5 T₁ Substituting T₂ = 0.8 T₁ 0.8 T₁ - 45 = 0.5 T₁ 0.3 T₁ = 45 T₁ = 150 K T₂ = 0.8 150 = 120 K Answer: 150 K, 120 K