An ideal gas undergoes cyclic process ABCDA as shown in given p-V diagram. What is the magnitude of amount of work done by the gas?

Step-by-step solution

The magnitude of work done by the gas in a cyclic process is equal to the area enclosed by the cycle on the P-V diagram. The given cycle ABCDA forms a rectangle. The width of the rectangle along the volume axis is V = 5V₀ - 3V₀ = 2V₀ . The height of the rectangle along the pressure axis is P = 4P₀ - 2P₀ = 2P₀ . Magnitude of work done |W| = Area of rectangle ABCD |W| = P V |W| = (2P₀) (2V₀) = 4P₀V₀ . Answer: 4 P₀ V₀