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AP EAMCET202021 Sep 2020Morning ShiftMathematicsCircleActual

The centre of a circle is ((2,-3) ) and the circumference is (10 ). Then its equation is

Options

  1. A(x^2+y^2+4 x+6 y+12=0 )
  2. B(x^2+y^2-4 x+6 y+12=0 )
  3. C(x^2+y^2-4 x+6 y-12=0 )
  4. D(x^2+y^2-4 x-6 y-12=0 )

Correct answer

C. (x^2+y^2-4 x+6 y-12=0 )

Step-by-step solution

Let the radius of required circle is ' (r ) ', so the circumference (=2 r=10 ) (given) ( r=5 ) and centre of required circle is ((2,-3) ) So, the equation of required circle is ( aligned (x-2)^2+(y+3)^2 & =25 x^2+y^2-4 x+6 y-12 & =0 aligned ) Hence, option (c) is correct.

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