Two rigid, thermally insulated tanks A and B are connected by a narrow tube fitted with a closed valve. Tank A has a volume of 5 L and contains an ideal gas at a pressure of 300 kPa and a temperature of 400 K. Tank B

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Quantrex Academy · Accepted Answer

Correct answer: B. 150 kPa

Conservation of internal energy for the insulated system gives:

U_A + U_B = U_f

n_A C_v T_A + n_B C_v T_B = (n_A + n_B) C_v T_f

n_A T_A + n_B T_B = n_f T_f

From the ideal gas equation,

PV = nRT

, which gives

nT = \dfrac{PV}{R}

. Substituting this into the energy equation:

\dfrac{P_A V_A}{R} + \dfrac{P_B V_B}{R} = \dfrac{P_f V_f}{R}

P_A V_A + P_B V_B = P_f (V_A + V_B)

Substituting the given values:

300(5) + 100(15) = P_f (5 + 15)

1500 + 1500 = 20 P_f

3000 = 20 P_f

P_f = 150

kPa

Answer:

150

kPa

Two rigid, thermally insulated tanks A and B are connected by a...

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