Two blocks, X and Y , are executing simple harmonic motion on smooth horizontal surfaces. Block X has mass M and is attached to a spring of force constant K . Block Y has mass 2M and is attached to a spring of force

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Correct answer: C. 2 : 1

For block X , the angular frequency is ω_X = (K)/(M) . For block Y , the angular frequency is ω_Y = (8K)/(2M) = (4K)/(M) = 2 (K)/(M) . The maximum speed of a block executing simple harmonic motion is given by v = Aω , which occurs at the mean position. Given that both blocks have identical speeds at their mean positions, v_X = v_Y . A_X ω_X = A_Y ω_Y A_X (K)/(M) = A_Y (2 (K)/(M) ) (A_X)/(A_Y) = (2)/(1) The ratio of the amplitude of block X to the amplitude of block Y is 2 : 1 . Answer: 2 : 1

Two blocks, X and Y , are executing simple harmonic motion on...

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