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NEET 2026
Exam
NEET
Year
2026
Subject
Physics
Chapter
Chapter

NEET 2026 · Physics · Chapter

A uniform wire of resistance R is cut into 6 equal segments. Three...

A uniform wire of resistance RR is cut into 66 equal segments. Three of these segments are connected in series to form a combination XX. The remaining three segments are connected in parallel to form a combination YY. If XX and YY are then connected in parallel with each other, what is the equivalent resistance of the entire arrangement?

Options

  1. AR20\dfrac{R}{20}
  2. B5R9\dfrac{5R}{9}
  3. C3R10\dfrac{3R}{10}
  4. DR36\dfrac{R}{36}

Correct answer

A. R20\dfrac{R}{20}

Step-by-step solution

Resistance of the uniform wire = RR

When cut into 66 equal segments, the resistance of each segment is r=R6r = \dfrac{R}{6}

Combination XX consists of 33 segments in series.

Resistance of XX, RX=3r=3×R6=R2R_X = 3r = 3 \times \dfrac{R}{6} = \dfrac{R}{2}

Combination YY consists of 33 segments in parallel.

Resistance of YY, RY=r3=13×R6=R18R_Y = \dfrac{r}{3} = \dfrac{1}{3} \times \dfrac{R}{6} = \dfrac{R}{18}

Combinations XX and YY are connected in parallel.

The equivalent resistance ReqR_{eq} is given by:

1Req=1RX+1RY\dfrac{1}{R_{eq}} = \dfrac{1}{R_X} + \dfrac{1}{R_Y}

1Req=2R+18R=20R\dfrac{1}{R_{eq}} = \dfrac{2}{R} + \dfrac{18}{R} = \dfrac{20}{R}

Req=R20R_{eq} = \dfrac{R}{20}

Answer: R20\dfrac{R}{20}
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