NEET2026PhysicsChapterActual
The magnetic field of a plane electromagnetic wave propagating in a vacuum is given by: B_x = 3 10⁻⁸ (6 10^8 t - 2 y ) T Which of the following expressions represents the corresponding electric field? (Here subscripts denote the direction of the field component)
Options
- AE_z = -9 (6 10^8 t - 2 y ) V/m
- BE_y = 9 (6 10^8 t - 2 y ) V/m
- CE_z = 9 (6 10^8 t - 2 y ) V/m
- DE_z = 10⁻¹⁶ (6 10^8 t - 2 y ) V/m
Correct answer
C. E_z = 9 (6 10^8 t - 2 y ) V/m
Step-by-step solution
The given magnetic field is B = 3 10⁻⁸ (6 10^8 t - 2 y ) i ; T . From the phase term (6 10^8 t - 2 y ) , the wave propagates in the +y direction. Thus, the direction of propagation is v = j . In an electromagnetic wave, the electric field E , magnetic field B , and the direction of propagation v are mutually perpendicular and satisfy the relation E B = v . Given B = i and v = j , we have: E i = j Since k i = j , the electric field must oscillate along the +z direction ( E = k ). The amplitude of the electric field