A researcher is adjusting a compound microscope to view a bacterial sample. The microscope has an objective lens of focal length 1.5 cm and an eyepiece of focal length 5.0 cm . If the researcher wants to achieve a total

Question

Quantrex Academy · Accepted Answer

Correct answer: C. 60 cm

The magnifying power of a compound microscope in normal adjustment (relaxed eye) is given by:

M = \dfrac{L}{f_o} \times \dfrac{D}{f_e}

where

L

is the tube length,

f_o

is the focal length of the objective,

f_e

is the focal length of the eyepiece, and

D

is the least distance of distinct vision.

Substituting the given values:

200 = \dfrac{L}{1.5} \times \dfrac{25}{5.0}

200 = \dfrac{L}{1.5} \times 5

L = \dfrac{200 \times 1.5}{5}

L = 40 \times 1.5 = 60\text{ cm}

Answer:

60\text{ cm}

A researcher is adjusting a compound microscope to view a bacterial...

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