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NEET2026PhysicsChapterActual

A student uses a Vernier callipers to measure the length of a metal cylinder. The main scale is graduated in millimeters ( 1 M.S.D. = 1 mm ), and 20 Vernier scale divisions (V.S.D.) coincide with 19 main scale divisions. When the jaws of the callipers are brought into contact with each other, the zero of the Vernier scale lies to the left of the main scale zero, and the 8^ th Vernier division coincides with a main sc

Options

  1. A3.43 cm
  2. B3.51 cm
  3. C3.47 cm
  4. D3.53 cm

Correct answer

D. 3.53 cm

Step-by-step solution

1 M.S.D. = 1 mm = 0.1 cm 20 V.S.D. = 19 M.S.D. 1 V.S.D. = 19 20 M.S.D. = 0.95 mm Least count (L.C.) = 1 M.S.D. - 1 V.S.D. = 1 mm - 0.95 mm = 0.05 mm = 0.005 cm Since the zero of the Vernier scale lies to the left of the main scale zero, the zero error is negative. Zero error = - (N - n) L.C. Zero error = - (20 - 8) 0.005 cm = -12 0.005 cm = -0.06 cm Measured value = M.S.R. + n' L.C. Measured value = 3.4 cm + 14 0.005 cm = 3.4 cm + 0.07 cm = 3.47 cm True length = Measured value - Zero error True length = 3.47 cm - (

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