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NEET 2026
Exam
NEET
Year
2026
Subject
Physics
Chapter
Chapter

NEET 2026 · Physics · Chapter

Two small carts of masses 8 kg and 12 kg are connected by a light...

Two small carts of masses 8 kg and 12 kg are connected by a light inextensible string and placed on a smooth horizontal
Two small carts of masses 8 kg8\text{ kg} and 12 kg12\text{ kg} are connected by a light inextensible string and placed on a smooth horizontal track as shown in the figure. A constant horizontal force of 50 N50\text{ N} is applied to the 12 kg12\text{ kg} cart, pulling the system. What is the magnitude of the tension in the string connecting the two carts?

Options

  1. A10 N10\text{ N}
  2. B30 N30\text{ N}
  3. C50 N50\text{ N}
  4. D20 N20\text{ N}

Correct answer

D. 20 N20\text{ N}

Step-by-step solution

Let the common acceleration of the two carts be aa.

Considering both carts as a single system, the total mass is M=8+12=20 kgM = 8 + 12 = 20\text{ kg}.

The net external force acting on the system is F=50 NF = 50\text{ N}.

Using Newton's second law, the acceleration of the system is:

a=FM=5020=2.5 m/s2a = \dfrac{F}{M} = \dfrac{50}{20} = 2.5\text{ m/s}^2

Let TT be the tension in the string connecting the two carts. Considering the free body diagram of the 8 kg8\text{ kg} cart, the only horizontal force acting on it is the tension TT.

Applying Newton's second law to the 8 kg8\text{ kg} cart:

T=m1a=8×2.5=20 NT = m_1 a = 8 \times 2.5 = 20\text{ N}

Answer: 20 N20\text{ N}
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