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NEET 2026
Exam
NEET
Year
2026
Subject
Physics
Chapter
Chapter

NEET 2026 · Physics · Chapter

A particle of mass 2m moving with speed v collides completely...

A particle of mass 2m2m moving with speed vv collides completely inelastically with another particle of mass 3m3m moving in the opposite direction with speed v2\dfrac{v}{2}. If the magnitude of the final velocity of the combined system is v′v', what is the ratio v:v′v : v'?

Options

  1. A10:710 : 7
  2. B5:25 : 2
  3. C1:101 : 10
  4. D10:110 : 1

Correct answer

D. 10:110 : 1

Step-by-step solution

By the principle of conservation of linear momentum:

m1v1+m2v2=(m1+m2)v′m_1 v_1 + m_2 v_2 = (m_1 + m_2) v'

Taking the direction of the first particle as positive and substituting the given values:

(2m)(v)+(3m)(−v2)=(2m+3m)v′(2m)(v) + (3m)\left(-\dfrac{v}{2}\right) = (2m + 3m)v'

2mv−3mv2=5mv′2mv - \dfrac{3mv}{2} = 5mv'

mv2=5mv′\dfrac{mv}{2} = 5mv'

v′=v10v' = \dfrac{v}{10}

Therefore, the ratio v:v′v : v' is 10:110 : 1.

Answer: 10:110 : 1
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