A uniform wooden stick is pivoted at one of its ends about a vertical axis perpendicular to its length, allowing it to rotate freely in a horizontal plane. If the mass of the stick is 150 g and its moment of inertia

Question

Quantrex Academy · Accepted Answer

Correct answer: B. 16.7 cm

The moment of inertia of a uniform rod of mass

m

and length

L

about an axis passing through one end and perpendicular to its length is given by:

I = \dfrac{m L^2}{3}

Given

m = 150 \text{ g}

and

I = 14000 \text{ g cm}^2

, substituting these values into the formula:

14000 = \dfrac{150 \times L^2}{3}

14000 = 50 L^2

L^2 = \dfrac{14000}{50} = 280

L = \sqrt{280} \approx 16.73 \text{ cm}

The length of the stick is nearly

16.7 \text{ cm}

.

Answer:

16.7 \text{ cm}

A uniform wooden stick is pivoted at one of its ends about a...

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