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NEET2026PhysicsChapterActual

A long, straight horizontal wire carries a steady current I from left to right as shown in the figure. Two circular conducting loops, P and Q, are placed in the same plane as the wire. Loop P is located above the wire and is moving vertically upwards with velocity v . Loop Q is located below the wire and is also moving vertically upwards with velocity v . According to Lenz's law, what will be the direction of the ind

Options

  1. AAnticlockwise in both P and Q
  2. BAnticlockwise in P and Clockwise in Q
  3. CClockwise in P and Anticlockwise in Q
  4. DClockwise in both P and Q

Correct answer

A. Anticlockwise in both P and Q

Step-by-step solution

According to the right-hand grip rule, the magnetic field produced by the straight current-carrying wire is directed out of the plane of the paper above the wire and into the plane of the paper below the wire. For loop P: It is located above the wire, so the magnetic field passing through it is directed outwards. As loop P moves vertically upwards (away from the wire), the strength of the magnetic field decreases, causing the outward magnetic flux to decrease. According to Lenz's law, the induced current will oppos

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