A steady conduction current I is used to charge a parallel plate capacitor having a plate area A . Which of the following gives the correct expression for the rate of change of the electric field ( dE dt ) in the gap between the plates?

Step-by-step solution

The electric field E between the plates of a parallel plate capacitor is given by E = q ₀ A , where q is the charge on the capacitor plates and A is the area of the plates. Differentiating both sides with respect to time t , we get: dE dt = 1 ₀ A dq dt The rate of change of charge on the plates is equal to the steady conduction current I , so dq dt = I . Substituting this into the equation, we obtain: dE dt = I ₀ A Alternatively, using the concept of displacement current I_d , we know that the displacement current