An open organ pipe produces a fundamental frequency of 300 Hz . If one of its ends is tightly closed, what will be the new fundamental frequency of the pipe?

Step-by-step solution

The fundamental frequency of an open organ pipe of length L is given by f_ open = v 2L . Given f_ open = 300 Hz . When one end of the pipe is tightly closed, it behaves as a closed organ pipe. The fundamental frequency of a closed organ pipe of the same length L is given by f_ closed = v 4L . Comparing the two frequencies, we get f_ closed = 1 2 ( v 2L ) = f_ open 2 . Substituting the given value, f_ closed = 300 2 = 150 Hz . Answer: 150 Hz