A radio wave emitted by a communication satellite propagates in free space with a wavelength of $300 \text{ m}$ . If the peak magnetic field of the electromagnetic wave is $1.5 \times 10^{-8} \text{ T}$ , what is the peak electric field of the wave?

(Speed of light in free space = $3 \times 10^8 \text{ m s}^{-1}$ )

Question

A radio wave emitted by a communication satellite propagates in free space with a wavelength of

300 \text{ m}

. If the peak magnetic field of the electromagnetic wave is

1.5 \times 10^{-8} \text{ T}

, what is the peak electric field of the wave?

(Speed of light in free space =

3 \times 10^8 \text{ m s}^{-1}

)

Quantrex Academy · Accepted Answer

Correct answer: B. 4.5 V m^ -1

The relationship between the peak electric field

E_0

and the peak magnetic field

B_0

in an electromagnetic wave propagating in free space is given by:

E_0 = c B_0

Substituting the given values:

E_0 = (3 \times 10^8 \text{ m s}^{-1}) \times (1.5 \times 10^{-8} \text{ T})

E_0 = 4.5 \text{ V m}^{-1}

Answer:

4.5 \text{ V m}^{-1}

A radio wave emitted by a communication satellite propagates in...