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NEET2026PhysicsChapterActual

A radio wave emitted by a communication satellite propagates in free space with a wavelength of 300 m . If the peak magnetic field of the electromagnetic wave is 1.5 10⁻⁸ T , what is the peak electric field of the wave? (Speed of light in free space = 3 10^8 m s ⁻¹ )

Options

  1. A4.5 10⁻⁶ V m ⁻¹
  2. B4.5 V m ⁻¹
  3. C5.0 10⁻¹⁷ V m ⁻¹
  4. D4.5 10⁻³ V m ⁻¹

Correct answer

B. 4.5 V m ⁻¹

Step-by-step solution

The relationship between the peak electric field E₀ and the peak magnetic field B₀ in an electromagnetic wave propagating in free space is given by: E₀ = c B₀ Substituting the given values: E₀ = (3 10^8 m s ⁻¹) (1.5 10⁻⁸ T ) E₀ = 4.5 V m ⁻¹ Answer: 4.5 V m ⁻¹

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