NEET2026PhysicsChapterActual
Ultraviolet light of wavelength 310 nm is directed at three different metal plates P, Q, and R. The work functions of these metals are 2.2 eV , 3.5 eV , and 4.8 eV respectively. Which of the metal plates will emit photoelectrons? (Take hc = 1240 eV nm )
Options
- AP and Q only
- BR only
- CP only
- DQ and R only
Correct answer
A. P and Q only
Step-by-step solution
The energy of the incident photon is given by E = hc Substituting the given values: E = 1240 eV nm 310 nm = 4.0 eV For photoelectric emission to take place, the energy of the incident photon must be greater than the work function of the metal ( E > ). For metal P: 4.0 eV > 2.2 eV (Emission occurs) For metal Q: 4.0 eV > 3.5 eV (Emission occurs) For metal R: 4.0 eV Thus, photoelectrons will be emitted from plates P and Q only. Answer: P and Q only