A parallel plate capacitor stores 40 mJ of electrostatic energy when connected across a 200 V DC supply. The capacitance of the capacitor is

Step-by-step solution

The energy stored in a capacitor is given by the formula: U = 1 2 C V^2 Given: U = 40 mJ = 40 10⁻³ J V = 200 V Substituting the values into the formula: 40 10⁻³ = 1 2 C (200)^2 40 10⁻³ = 1 2 C 40000 40 10⁻³ = 20000 C C = 40 10⁻³ 20000 C = 2 10⁻⁶ F C = 2 F Answer: 2 F