A student uses an error-free screw gauge to measure the thickness of a uniform glass plate. The pitch of the screw gauge is 0.5 mm and there are 50 divisions on its circular scale. During the measurement, the linear

Question

Quantrex Academy · Accepted Answer

Correct answer: B. 0.284 cm

Least count of the screw gauge is given by:

\text{LC} = \dfrac{\text{Pitch}}{\text{Number of divisions on circular scale}}

\text{LC} = \dfrac{0.5\text{ mm}}{50} = 0.01\text{ mm}

The thickness of the glass plate is calculated as:

\text{Thickness} = \text{Linear scale reading} + (\text{Circular scale reading} \times \text{LC})

\text{Thickness} = 2.5\text{ mm} + (34 \times 0.01\text{ mm})

\text{Thickness} = 2.5\text{ mm} + 0.34\text{ mm} = 2.84\text{ mm}

Converting to centimeters:

2.84\text{ mm} = 0.284\text{ cm}

Answer:

0.284\text{ cm}

A student uses an error-free screw gauge to measure the thickness...

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