A uniform straight bar magnet has a magnetic dipole moment . It is carefully bent at its exact center to form a V-shape, such that the angle between the two halves is 120^ . The new magnetic dipole moment of the system will be:

Step-by-step solution

Let the initial length of the bar magnet be 2l and its pole strength be m . The initial magnetic dipole moment is given by = m(2l) . When the magnet is bent at its exact center, it forms two arms of equal length l . The angle between these two arms is given as 120^ . The new distance d between the North and South poles can be calculated using the cosine rule in the triangle formed by the two arms: d = l^2 + l^2 - 2(l)(l) (120^ ) Substituting (120^ ) = - 1 2 : d = 2l^2 - 2l^2 (- 1 2 ) = 2l^2 + l^2 = 3 l The new magn