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NEET2026PhysicsChapterActual

The given graph shows the variation of de Broglie wavelength ( ) with the inverse of velocity ( 1/v ) for two different particles A and B. If m_A and m_B are the respective masses of particles A and B, which of the following relations is correct?

Options

  1. Am_A > m_B
  2. Bm_A < m_B
  3. Cm_A = m_B
  4. DThe relationship depends on the charges of the particles

Correct answer

B. m_A < m_B

Step-by-step solution

The de Broglie wavelength of a particle is given by the relation: = h mv This can be rewritten as: = ( h m ) ( 1 v ) Comparing this with the equation of a straight line y = mx , the graph of versus 1/v is a straight line passing through the origin with a slope equal to h m . From the given graph, the slope of line A is greater than the slope of line B. Slope _A > Slope _B h m_A > h m_B Since h is a positive constant, this implies: m_A Answer: m_A < m_B

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