NEET2026PhysicsChapterActual
Two simple pendulums are suspended from the same rigid support and start oscillating in phase from their mean positions. They are observed to be in phase again at the mean position for the first time after the shorter pendulum has completed exactly 7 oscillations. What is the ratio of the length of the longer pendulum to that of the shorter pendulum?
Options
- A36 : 49
- B49 : 36
- C7 : 6
- D6 : 7
Correct answer
B. 49 : 36
Step-by-step solution
Let T_S and T_L be the time periods of the shorter and longer pendulums respectively, and L_S and L_L be their lengths. For the two pendulums to be in phase again at the mean position for the first time, they must have completed an integer number of oscillations, and the shorter pendulum must have completed exactly one more oscillation than the longer pendulum. Given that the shorter pendulum completes 7 oscillations, the longer pendulum must have completed 7 - 1 = 6 oscillations in the same time interval. Equating