A monochromatic ray of light has a wavelength of 480 nm in a transparent medium X and 600 nm in a transparent medium Y . When the light ray travels from medium X to medium Y , the critical angle for total internal reflection at their interf

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A monochromatic ray of light has a wavelength of 480 nm in a transparent medium X and 600 nm in a transparent medium Y . When the light ray travels from medium X to medium Y , the critical angle for total internal reflection at their interface is:

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Correct answer: C. ⁻¹ ( 4 5 )

The refractive index of a medium is inversely proportional to the wavelength of light in it, n 1 . The refractive indices of medium X and medium Y are n_X = c f _X and n_Y = c f _Y . The critical angle _c for total internal reflection at the interface when light travels from a denser medium X to a rarer medium Y is given by _c = n_Y n_X . Substituting the expressions for refractive indices, we get _c = _X _Y . Given _X = 480 nm and _Y = 600 nm , we have _c = 480 600 = 4 5 . Therefore, _c = ⁻¹ ( 4 5 ) . Answer: ⁻¹ (

A monochromatic ray of light has a wavelength of 480 nm in a transparent medium X and 600 nm in a transparent medium Y . When the light ray travels from medium X to medium Y , the critical angle for total internal reflection at their interface is:

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