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NEET 2026
Exam
NEET
Year
2026
Subject
Physics
Chapter
Chapter

NEET 2026 · Physics · Chapter

A body starts from rest and moves with uniform acceleration along a...

A body starts from rest and moves with uniform acceleration along a straight horizontal track. Let d1d_1 be the distance covered by the body in the pthp^{\text{th}} second of its motion, and d2d_2 be the total distance covered by it in the first pp seconds. The ratio d1d2\dfrac{d_1}{d_2} is:

Options

  1. A2p−1p2\dfrac{2p-1}{p^2}
  2. B2p+1p2\dfrac{2p+1}{p^2}
  3. C2p−12p\dfrac{2p-1}{2p}
  4. Dp22p−1\dfrac{p^2}{2p-1}

Correct answer

A. 2p−1p2\dfrac{2p-1}{p^2}

Step-by-step solution

Initial velocity u=0u = 0.

Distance covered in the pthp^{\text{th}} second is given by:

d1=u+a2(2p−1)=a2(2p−1)d_1 = u + \dfrac{a}{2}(2p - 1) = \dfrac{a}{2}(2p - 1)

Total distance covered in the first pp seconds is given by:

d2=up+12ap2=12ap2d_2 = up + \dfrac{1}{2}ap^2 = \dfrac{1}{2}ap^2

The ratio d1d2\dfrac{d_1}{d_2} is:

d1d2=a2(2p−1)12ap2=2p−1p2\dfrac{d_1}{d_2} = \dfrac{\dfrac{a}{2}(2p - 1)}{\dfrac{1}{2}ap^2} = \dfrac{2p - 1}{p^2}

Answer: 2p−1p2\dfrac{2p-1}{p^2}
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