NEET2026PhysicsChapterActual
A light helical spring is compressed by 2 cm when a horizontal force of 40 N is applied to it. A block of mass 5 kg is then attached to one end of this spring while the other end is fixed to a rigid wall. If the block is set into simple harmonic motion on a frictionless horizontal surface, what is the time period of its oscillation?
Options
- A3.14 s
- B0.157 s
- C0.314 s
- D0.0314 s
Correct answer
C. 0.314 s
Step-by-step solution
The spring constant k is given by the restoring force per unit extension. k = F x = 40 0.02 = 2000 N/m The time period of simple harmonic motion for a spring-mass system is given by: T = 2 m k Substituting the given values m = 5 kg and k = 2000 N/m : T = 2 5 2000 T = 2 1 400 T = 2 1 20 T = 10 T = 3.14 10 = 0.314 s Answer: 0.314 s