NEET2026PhysicsChapterActual
The given graph shows the variation of the restoring force F developed in a spring as a function of its displacement x from its natural length. Based on the graph, what is the spring constant of the spring, and what will be the restoring force when the displacement is x = +5 cm ?
Options
- A500 N m ⁻¹ and -25 N
- B500 N m ⁻¹ and +25 N
- C5 N m ⁻¹ and -0.25 N
- D50 N m ⁻¹ and -2.5 N
Correct answer
A. 500 N m ⁻¹ and -25 N
Step-by-step solution
From the given graph, the restoring force F and displacement x follow the relation F = -kx , where k is the spring constant. At x = -2 cm = -0.02 m , the restoring force is F = 10 N . Substituting these values into the equation: 10 = -k(-0.02) k = 10 0.02 = 500 N m ⁻¹ To find the restoring force when the displacement is x = +5 cm = +0.05 m : F = -kx = -500 0.05 = -25 N Thus, the spring constant is 500 N m ⁻¹ and the restoring force is -25 N . Answer: 500 N m ⁻¹ and -25 N