In the circuit shown below, two non-ideal cells are connected in parallel across an external resistor R = 2 . Cell 1 has an emf E₁ = 8 V and internal resistance r₁ = 1 . Cell 2 has an emf E₂ = 4 V and internal resistance r₂ = 2 . Both cells are connected with their positive terminals to the same upper junction. Which of the following correctly describes the magnitude of the current passing through Cell 2 and its oper

Step-by-step solution

Let the potential of the lower junction be 0 V and the upper junction be V . Applying Kirchhoff's Current Law at the upper junction: V - 8 1 + V - 4 2 + V 2 = 0 Multiplying the equation by 2 : 2(V - 8) + (V - 4) + V = 0 2V - 16 + V - 4 + V = 0 4V = 20 V = 5 V The current through Cell 2 is: I₂ = V - E₂ r₂ = 5 - 4 2 = 0.5 A Since V > E₂ , the current flows from the upper junction into the positive terminal of Cell 2. Therefore, Cell 2 is being charged. Answer: 0.5 A , being charged