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NEET2026PhysicsChapterActual

The position-time ( x-t ) graph of a particle moving along a straight line is shown in the figure. The graph is divided into three distinct segments: OP, PQ, and QR. Which segment of the graph represents motion with negative acceleration?

Options

  1. ASegment OP
  2. BSegment PQ
  3. CSegment QR
  4. DBoth segments OP and QR

Correct answer

C. Segment QR

Step-by-step solution

The slope of the position-time ( x-t ) graph represents the velocity of the particle, v = dx dt . The rate of change of this slope represents the acceleration, a = d^2x dt^2 . In segment OP, the curve is concave upwards, indicating that the slope (velocity) is increasing. Hence, the acceleration is positive ( a > 0 ). In segment PQ, the graph is a straight line, indicating a constant slope (velocity). Hence, the acceleration is zero ( a = 0 ). In segment QR, the curve is concave downwards, indicating that the slope

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