NEET2026PhysicsChapterActual
A simple pendulum is released from rest at its extreme right position (labeled B) at time t = 0 , as shown in the figure. If T is the time period of its oscillation, which of the following statements correctly describes the time variation of its kinetic energy ( K ) and potential energy ( U )? (Assume potential energy is zero at the mean position O)
Options
- AThe kinetic energy K becomes zero at t = T 4 and maximum at t = T 2 .
- BThe potential energy U becomes zero at t = T 4 , while the kinetic energy K becomes maximum at t = T 4 .
- CBoth kinetic and potential energies oscillate with a time period of T .
- DThe kinetic energy K reaches its first maximum at t = T 2 .
Correct answer
B. The potential energy U becomes zero at t = T 4 , while the kinetic energy K becomes maximum at t = T 4 .
Step-by-step solution
The simple pendulum is released from rest at the extreme right position B at t = 0 . The time taken to travel from the extreme position to the mean position O is T 4 . At the mean position ( t = T 4 ), the velocity of the pendulum is maximum, resulting in maximum kinetic energy K . The potential energy U is given to be zero at the mean position O . Therefore, U becomes zero at t = T 4 . The kinetic and potential energies oscillate with a time period of T 2 , not T . Thus, the potential energy U becomes zero at t =