A uniform cylindrical wire has a measured mass of 18.75 g and a length of 7.3 cm. Keeping the significant figures in view, the linear mass density of the wire can be best expressed as Y 10⁻¹ kg m ⁻¹ , where the value of Y is :

Step-by-step solution

Mass of the wire, m = 18.75 g = 18.75 10⁻³ kg Length of the wire, l = 7.3 cm = 7.3 10⁻² m Linear mass density, = m l = 18.75 10⁻³ 7.3 10⁻² = 2.568 10⁻¹ kg m ⁻¹ The number of significant figures in the measured mass is 4 and in the measured length is 2 . In division, the final result should retain as many significant figures as are present in the original value with the least significant figures. Therefore, the result must be rounded off to 2 significant figures. Rounding 2.568 to 2 significant figures, we get 2.6 .