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NEET2026PhysicsChapterActual

In the circuit shown, an alternating voltage V(t) = 12 ( t) V is applied across a series combination of an ideal diode and a resistor R . Which of the following correctly gives the maximum magnitude of the voltage across the diode ( |V_D|_ ) and the maximum magnitude of the voltage across the resistor ( |V_R|_ ) over one complete cycle?

Options

  1. A|V_D|_ = 12 V, |V_R|_ = 12 V
  2. B|V_D|_ = 0 V, |V_R|_ = 12 V
  3. C|V_D|_ = 12 V, |V_R|_ = 0 V
  4. D|V_D|_ = 6 2 V, |V_R|_ = 6 2 V

Correct answer

A. |V_D|_ = 12 V, |V_R|_ = 12 V

Step-by-step solution

The input alternating voltage is given by V(t) = 12 ( t) V. During the positive half-cycle ( V(t) > 0 ), the ideal diode is forward-biased and acts as a short circuit. Therefore, the voltage drop across the diode is zero ( V_D = 0 ). The entire input voltage appears across the resistor R . V_R = V(t) = 12 ( t) The maximum magnitude of the voltage across the resistor is |V_R|_ = 12 V. During the negative half-cycle ( V(t) V_D = V(t) = 12 ( t) The maximum magnitude of the voltage across the diode during this half-cyc

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