A transverse wave propagating on a stretched string is given by the equation y(x, t) = 5.0 2 (12 t - 0.05 x) , where x and y are expressed in cm and t is in seconds. The phase difference between two particles on the string separated by a distance of 0.3 m is :

Step-by-step solution

The given wave equation is y(x, t) = 5.0 2 (12 t - 0.05 x) . Comparing this with the standard wave equation y(x, t) = A ( t - k x) , we get the wave number k = 2 0.05 = 0.1 cm ⁻¹ . The phase difference between two points separated by a distance x is given by = k x . Given the separation distance x = 0.3 m = 30 cm. Substituting the values, we get: = 0.1 30 = 3 rad. Answer: 3 rad