NEET2026PhysicsChapterActual
A toy car of mass 10 kg is placed on a smooth horizontal floor. Two horizontal forces of 15 N and 20 N act on it simultaneously along the positive x-axis and positive y-axis, respectively. The magnitude of its acceleration and the angle its direction of motion makes with the x-axis are respectively :
Options
- A2.5 m s ⁻² ; ⁻¹ ( 4 3 )
- B2.5 m s ⁻² ; ⁻¹ ( 3 4 )
- C3.5 m s ⁻² ; ⁻¹ ( 4 3 )
- D25 m s ⁻² ; ⁻¹ ( 3 4 )
Correct answer
A. 2.5 m s ⁻² ; ⁻¹ ( 4 3 )
Step-by-step solution
The net force acting on the toy car is F = 15 i + 20 j . The magnitude of the net force is | F | = 15^2 + 20^2 = 225 + 400 = 25 N. The magnitude of acceleration is a = | F | m = 25 10 = 2.5 m s ⁻² . The angle the direction of motion makes with the x-axis is given by = F_y F_x = 20 15 = 4 3 . Thus, = ⁻¹ ( 4 3 ) . Answer: 2.5 m s ⁻² ; ⁻¹ ( 4 3 )